11y^2-19y-10=-4y

Solution for 11y^2-19y-10=-4y equation:

11y^2-19y-10=-4y

We move all terms to the left:

11y^2-19y-10-(-4y)=0

We get rid of parentheses

11y^2-19y+4y-10=0

We add all the numbers together, and all the variables

11y^2-15y-10=0

a = 11; b = -15; c = -10;
Δ = b2-4ac
Δ = -152-4·11·(-10)
Δ = 665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{665}}{2*11}=\frac{15-\sqrt{665}}{22}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{665}}{2*11}=\frac{15+\sqrt{665}}{22}
$